Every teacher of electronics knows the look. A student has assembled a circuit that should work, flipped the switch, and nothing has happened. The motor sits there. The face falls.
That moment is the best thing that will happen in the lesson — as long as you treat it as a physics question rather than a failure.
The dead-motor moment
A formula on a whiteboard is abstract. V = I × R is easy to copy down and easy to forget by Friday. But a robot that will not move is a problem the student personally cares about, and almost every reason it will not move is electrical:
- A wire is loose, so the circuit is not actually a loop and no current can flow.
- The battery pack is flat, so there is not enough voltage to push current through the motor.
- A connection is poor, adding resistance where there should be almost none.
- Positive and negative are swapped, so the motor runs backwards — or, with an LED, does not light at all.
Each of these is Ohm's law wearing a disguise. The student who finds the fault is not recalling a fact; they are using the idea to get something they want.
Ohm's law in one line
Younger students do well with a water-pipe picture. Voltage is the pressure pushing water along. Current is how much water actually flows past each second. Resistance is how narrow the pipe is. For the same pressure, a narrower pipe carries less flow.
Rearranged, it tells you what you can predict:
| If you know… | You can find… | Using |
|---|---|---|
| Voltage and resistance | How much current flows | I = V ÷ R |
| Current and resistance | The voltage across a part | V = I × R |
| Voltage and current | The resistance of a part | R = V ÷ I |
A worked example on the bench
The Stage 1 kit is a good place to try this, because it ships with a 4×AA battery holder, LEDs and 1K resistors — everything you need to see the numbers turn into light.
Four AA cells give roughly 6 V. A red LED needs about 2 V across it to glow, which leaves about 4 V for the resistor to absorb. With a 1,000 Ω (1K) resistor in series:
I = V ÷ R = 4 V ÷ 1,000 Ω = 0.004 A (4 mA)
Enough for a clearly visible LED, and comfortably below what the LED can handle.
Now ask the class to predict what happens if the resistor is swapped for a smaller one, say 330 Ω. Less resistance, so more current — around 12 mA — and a brighter LED. Then let them swap it and see. Being right about something invisible is a surprisingly powerful feeling.
Ask the reverse question too: what happens with no resistor? That is the conversation where students discover why the resistor is in the circuit at all.
Different LED colours drop different voltages — roughly 1.8 V for red up to about 3 V for blue or white. The maths is identical; only the "leftover" voltage for the resistor changes. It makes a nice extension for faster finishers.
Where it shows up when things break
Once students have the idea, they start spotting it everywhere in the build:
- The robot slows down over a session. As batteries drain, the voltage they can deliver under load falls, and the motors get less push.
- One wheel is weaker than the other. A poor joint on one side adds resistance, so less current reaches that motor.
- Long, thin wires misbehave. Every wire has some resistance, and it adds up over distance, so keep runs short and connections tight.
- The LED is dim, or dies. The wrong resistor is either choking the current or letting too much through.
None of these need a lecture. A student who has met the idea once at the bench will usually connect it on their own, and that connection is what makes the lesson stick.
How to run it in class
The routine we use is simple and works from about Grade 5 upwards:
- Predict. Before wiring anything, students write down what they expect to happen and why.
- Build and measure. They wire the circuit and, if you have multimeters, measure the voltage across the resistor and LED.
- Explain the gap. When the prediction and the reading disagree — and they often do — students work out why. That gap is where the learning happens.
Give each pair one LED, one battery holder and two resistors of different values. Ask: "Which resistor will make the LED brighter — and how do you know before you try?" Let them argue, then test it.
A textbook can show you the formula. A robot gives you a reason to need it.


